Read all three pages. Data transcribed, G computed, graph plotted. Here's the key result first, then the print-ready record.

Numbers from your four readings (L = 300 mm, d = 10 mm, J = πd⁴/32 = 981.75 mm⁴, G = TL/Jθ):

Mean G ≈ 3.90 × 10⁴ N/mm² (39.0 GPa); graph-slope method gives 3.79 × 10⁴ N/mm².

One thing to be ready for in viva: the linearity is superb (R² = 0.9994, so your procedure was clean) but the value is ~half the standard 0.8 × 10⁵ N/mm² for mild steel. That is a systematic offset, not scatter — the two honest causes are (i) slip at the chucks inflating θ, or (ii) the actual twisted length being longer than the 300 mm gauge length you used. Since G ∝ L, an effective grip-to-grip length near 600 mm puts you right back at ~78 GPa. I've written this up as a discussion note in the record rather than hiding it — much better than a fudged number.

Printing notes

• 4 A4 pages: (1) header + aim + apparatus + formulae + procedure + line diagram + observation table, (2) the graph on its own graph-sheet-style page to cut and paste at "Graph :", (3) calculations + error discussion + result + precautions, (4) 12 viva questions with answers + reference values.
• Print from a browser with margins "Default", background graphics on so the grid and table shading come through.
• Marks and Faculty sign left blank; Date is filled as 18/09/2026 — overwrite if you submit on another day.
• If your teacher wants the graph redrawn by hand on real graph paper, the plotted points are (4.905, 2.1), (9.81, 4.3), (14.715, 6.8), (19.62, 9.2) in N·m and degrees, with best-fit slope 0.4617°/N·m — that reproduces the printed figure exactly.